Talk:The Longest Article

Don't sit on that pew. That's where I hid the photographs! --hugebob 18:42, 12 Jumbly 2009 (UTC)

Oops, sorry. --Galanoth 18:44, 12 Jumbly 2009 (UTC)

The current longest article on illogicopedia is Wheeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee. It has 787, 625 bytes

• (hist) ‎Wheeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee ‎[787,625 bytes]

• (hist) ‎Moar ‎[348,500 bytes]

• (hist) ‎Stub ‎[153,777 bytes]

• (hist) ‎Kajillion ‎[151,895 bytes]

• (hist) ‎The longest article...ever ‎[142,495 bytes]

• (hist) ‎Chuck Norris ‎[96,784 bytes]

• (hist) ‎Super Smash Bros. Melee cheats/7 ‎[89,295 bytes]

• (hist) ‎Anagrams for Illogicopedia ‎[78,682 bytes]

• (hist) ‎Super Smash Bros. Melee cheats/8 ‎[75,063 bytes]

• (hist) ‎Super Smash Bros. Melee cheats/6 ‎[74,207 bytes]

• (hist) ‎ᏴᏑ ‎[71,553 bytes]

• (hist) ‎Super Smash Bros. Melee cheats/1 ‎[58,146 bytes]

• (hist) ‎Shaggy Dog Story ‎[57,089 bytes]

• (hist) ‎ASCII Nazi ‎[54,041 bytes]

• (hist) ‎The Longest Article ‎[46,639 bytes] <-----This article is here as over 5 seconds ago. !15th place...

- ₪ Ragglefraggleking ₪ Is ₪ Eating ₪ Your ₪ Bagels 15:41, 14 Jumbly 2009 (UTC)

My suggestion! Take parts from each of those article (ie the list of chukc facts, the repetive "weeeeeee", ect. ₪ Ragglefraggleking ₪ Is ₪ Eating ₪ Your ₪ Bagels 15:44, 14 Jumbly 2009 (UTC)

I think it's goal is to be the longest article, but also maintain some form of content. Because the top 4 articles in length have no actual reason to read. I just like to add stuff here if I have an idea or just am bored. --T3 15:48, 14 Jumbly 2009 (UTC)

Yeah. Let's add some content - maybe some info about long articles. --Galanoth 16:05, 14 Jumbly 2009 (UTC)

I added some funny stuff about drugs. --T3 16:58, 14 Jumbly 2009 (UTC)

Without the World's Longest Sentence (which I wrote, by the way), this article would be nothing. Nothing. —rms talk 04:25, 16 Jumbly 2009 (UTC)

Probably. --Galanoth 06:24, 16 Jumbly 2009 (UTC)

Hey, I just created Too many With 1,035,799 bytes.

Wow. I actually quite like this article. -- Hindleyak  Converse • ?blog • Click here! 19:57, 16 Arply 2010 (UTC)

Actually

n² - 10 = n + 2n n² - 10 = 3n -n² -n² 10 = 2n ÷2 ÷2 5 = n

is

Failed to parse (syntax error): {\displaystyle n² - 10 = 3n}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n² -3n - 10 = 0}

/insert into quadratic

${\frac {3\pm {\sqrt {9+40}}}{2}}$

${\frac {3\pm 7}{2}}$

$,n=5,-2$

Check your math next time. —rms talk 05:27, 24 Arply 2010 (UTC)

Also, you can take this alternative factoring method:

n² - 10 = n + 2n

n² - 10 = 3n

n² -3n - 10 = 0

(n - 5)(n + 2) = 0

n = 5, -2

Geesh. —rms talk 05:32, 24 Arply 2010 (UTC)

1. Fuck you.
2. I'm ashamed to admit it, but I can get into any advanced class I want except math. I've always been the best in mainstream classes but I suck at it compared to everything else. But realistically, I made the problem with the intent of the number being 5. I never thought of anything else. Technically I'm not wrong but I'm not completely right. Logic, eh? --T3 15:40, 24 Arply 2010 (UTC)

I know

...this was a troll edit, but it at least made me smirk slightly. -- Hindleyak  Converse • ?blog • Click here! 18:54, 15 Octodest 2010 (UTC)

Accident

I accidentally changed the article to its first edit. Now I'll need a mainframe to return it to its proper form.

Kate (talk)

6^123456?

Someone on a past revision of this article had posted the digits of pow(6,123456) claiming to have calculated it with Python. It was wrong though so here's the correct digits. I made it with a small handcoded C program. They really are the correct digits. Simplest test: copy the digits to a file and wc. Then calculate ceil(123456*log10(6)). You'll get the same size.

Test 2: Using Python or anything else supporting bigints compute this number and match. If it cant go till that size calc. to a lower power of six, (say 123456/n) and then raise a number made from the first few digits of that number to the power of n. The digits you get should match with the initial digits of my result.

It's too late in the night so I'll be able format this into a line-by-line dump only by tommorrow.

Lord Assbutt the Fourth (talk) 18:29, 25 Yoon 2014 (UTC)